The eigenvectors of $A$ do not change direction when you multiply them by $A$. The output $Ax$ is on the same line as the input vector $x$.
$$Ax = \lambda x$$
Multiply again by $A$, to see that $x$ is also an eigenvector of $A^2$:
$$A^k x = \lambda^k x$$
The eigenvalues of any triangular matrix is its main diagonal elements.
Spectral theorem: Every real symmetric matrix has the form $S = Q \Lambda Q^\text{T}.$
A positive definite matrix has all positive eigenvalues.
If $\lambda \geq 0$ but not $\lambda \gt 0$ then it is positive semidefinite.
Elimation factors every positive definite $S$ into $A^\text{T}A$ (A is upper triangular)
This is Cholesky factorization $S = A^{\text{T}}A$ with $\sqrt{\text{pivots}}$ on the main diagonal of $A$.